Answer : The number of moles of \(N_2\) are, 0.03 mole
Solution :
Using ideal gas equation,
\(PV=nRT\)
where,
P = pressure of the gas = 300 kpa = 2.96 atm
conversion : 1 atm = 101.325 kpa
V = volume of the gas = 250 ml = 0.250 L
conversion : 1 L = 1000 ml
T = temperature of the gas = 300 K
R = universal gas constant = 0.0821 Latm/moleK
n = number of moles of gas
Now put all the given values in the above formula, we get the number of moles of gas.
\(2.96atm\times 0.250L=n\times 0.0821Latm/moleK\times 300K\)
\(n=0.03mole\)
Therefore, the number of moles of \(N_2\) are, 0.03 mole
