Kelsie sold digital cameras on her website. She bought the cameras for $65 each and included a 60% markup to get the selling price. To the nearest dollar, what was the selling price for one camera?
Find 60% of 65 then add it to 65:
0.6 * 65 = 39
Now add it to 65:
39 + 65 = 104
So she's selling camera's for $104 each.
Answer:
$104.
Step-by-step explanation:
We have been given that Kelsie bought the cameras for $65 each and included a 60% markup to get the selling price.
The selling price of one camera will be equal to the cost of camera plus markup that is $65 plus 60% of $65.
\(\text{Selling price of one camera}=\$65+(\frac{60}{100}\times \$65)\)
\(\text{Selling price of one camera}=\$65+(0.60\times \$65)\)
\(\text{Selling price of one camera}=\$65+\$39\)
\(\text{Selling price of one camera}=\$104\)
Therefore, the selling price of each camera is $104.