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ajluv3161

the axis of symmetry is 2
2x^2-8x+8
2(x^2-4x)+8
2(x-2)^2-2(4)+8
2(x-2)^2-8+8
2(x-2)^2
     ^ on a graph would be at x=2

Answer: 2 is the axis of symmetry for the given function.

Step-by-step explanation:

Given function \(f(x) = 2x^2-8x + 8\)    -------(1)

Since, the axis of symmetry is a line which divides the parabola into two equal halves that are the reflection of each other.

And, a quadratic function represents a parabola.

If a parabola is in the form of \(ax^2+bx+c\),

Then, axis of symmetry, \(x=-\frac{b}{2a}\)

Thus, axis of symmetry for the parabola represented by equation (1)

\(x=-\frac{-8}{2\times 2}=2\)

⇒x=2



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