Verified Answer :

konrad509

\(4(x-1)^2+2=10 \\ 4(x-1)^2=8\\ (x-1)^2=2\\ x-1=-\sqrt2 \vee x-1=\sqrt2\\ x=1-\sqrt2 \vee x=1+\sqrt2\)

Lilith

\(4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}\)

\(Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}\)