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GIVEN: ABCD is a rectangle

Diagonals AC and BD intersect at E


PROVE:Triangle AEB is isosceles

GIVEN: ABCD is a rectangle Diagonals AC and BD intersect at E PROVE:Triangle AEB is isosceles class=

Verified Answer :

Because both diagonals AC and BD are the same length, that means that where they intersect at is the same length(i.e AE and BE). Since those are the same, that means that this triangle should be an isosceles triangle, with at least 2 sides having the same length.

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