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harricat001

2x2+2x\(\sqrt{(2/2) x^{2} +3 x^{2} } +2 x \sqrt{(2/2) x^{2} +3 x^{2} }\)
The answer is about 16.649

Answer:

Lateral area of a regular pyramid with square is 12.64 square unit

Step-by-step explanation:

Given : A regular pyramid with base is a square.

We have to find the  lateral area for the regular pyramid.

Lateral area of a regular pyramid with square =  \(a\sqrt{a^2+4h^2}\)

Where, a is side of square

and h is height of pyramid.

Substitute, a = 2

and h = 3

we have,

Lateral area of a regular pyramid with square =  \(2\sqrt{(2)^2+4(3)^2}\)


Simplify, we have,

Lateral area of a regular pyramid with square = 12.64

Thus, The Lateral area of a regular pyramid with square is 12.64 square unit

                   












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Question

Find the lateral area for the regular pyramid.

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