The produced grams of \(H_2O\) is \(36 \ g\).
In the metric system, a gram is defined as one thousandth \((1 \times 10^{-3})\) of a kilogram.
How do determine the number of moles?
\(\mathrm{Number \ of \ moles} = \frac{\mathrm{Mass}}{ \mathrm{Molar \ mass}}\)
\($\mathrm{NaOH}+\mathrm{HCl} \longrightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}$\)
1 mol of \($\mathrm{NaOH}$\) reacts with 1 mol of \($\mathrm{HCl}$\) and produces \($1 \mathrm{~mol}$\)of \($\mathrm{NaCl}$\) and 1 mol of \($\mathrm{H}_{2} \mathrm{O}$\) Number of moles of \($\mathrm{NaCl}$\)
\($\begin{aligned}&=\frac{\text { mass }}{\text { molar mass }} \\&=\frac{116 \mathrm{~g}}{58.44 \mathrm{~g} / \mathrm{mol}} \\&=1.98 \mathrm{~mol}\end{aligned}$\)
Number of moles produced \($\mathrm{H}_{2} \mathrm{O}=1.98 \mathrm{~mol}$\)
Amount of produced \($\mathrm{H}_{2} \mathrm{O}$\)
\(\mathrm{= mole \ number $\times$ molar mass}\)
\($=1.98 \mathrm{~mol} \times 18 \mathrm{~g} / \mathrm{mol}$\)
\(\begin{aligned}&=35.64 \mathrm{~g} \\&=36 \mathrm{~g}\end{aligned}$\)
Therefore, produced grams of \(H_2O\) is \(36 \ g\).
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