Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?
Anita is 17 years old now
6 years ago she was 17- 6 years = 11 years
thus 6 years ago Ben is P 11 years old
therefore Ben will be P 11 + 6 years old now
Ben is \(\frac{P}{11}+6\) old now in terms of P .
A linear equation in two variables is of the form Ax + By + C = 0, in which A and B are the coefficients, C is a constant term, and x and y are the two variables, each with a degree of 1. For example, 7x + 9y + 4 = 0 is a linear equation in two variables. If we consider two such linear equations, they are called simultaneous linear equations.
According to the question
Six years ago Anita was P times as old as Ben was.
Let Ben's age now be B.
Anita's age now is A.
Writing linear equation in two variables
(A-6) = P(B-6)
But A is 17 and therefore
17 - 6 = P(B - 6)
11 = P(B - 6)
\(\frac{11}{P}\) = (B-6)
\(B = \frac{P}{11}+6\)
Hence,
Ben is \(\frac{P}{11}+6\) old now in terms of P .
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