Kim and Courtney share a 16-ounce of box of cereal.  By the end of the week, Kim has eaten 3/8 of the box, and Courtney has eaten 1/4 of the box of cereal.  What fraction of the box is left?

Verified Answer :

No. of ounces Kim ate = 3/8 16 = 6 ounces
No. of ounces Courtney ate = 1/4
16 = 4 ounces
No. of ounces left = Total amt. of cereals - Kim's share - Courtney's share
                          = 16 - 6 - 4 =6 ounces
Fraction of left over cereal = 6/16 = 3/8

³/₈

Further explanation

We will solve the problem of subtraction between fractions.

Given:

Kim and Courtney share a 16-ounce of the box of cereal.  

By the end of the week:

  • Kim has eaten ³/₈ of the box, and
  • Courtney has eaten ¹/₄ of the box of cereal.  

Question:

What fraction of the box is left?

The Process:

Kim has eaten ³/₈ of the box of cereal. Let's calculate how many fractions of the box are left after Kim has eaten them.

\(\boxed{ \ 1 - \frac{3}{8} = \ ? \ }\)

\(\boxed{ \ \frac{8}{8} - \frac{3}{8} = \frac{5}{8} \ }\)

Hence, the rest of the box after Kim has eaten ³/₈ of the box is

\(\boxed{\boxed{ \ \frac{5}{8} \ }}\)

Furthermore, Courtney has eaten ¹/₄ of the box of cereal. Let's calculate how many fractions of the box are left again after Courtney ate the remaining part since Kim had eaten it before.

\(\boxed{ \ \frac{5}{8} - \frac{1}{4} = \ ? \ }\)

Before we subtract, the denominator must be equated. Prepare ¹/₄ to be ²/₈. The numerator and denominator are multiplied by two.

\(\boxed{ \ \frac{5}{8} - \frac{2}{8} = \frac{3}{8} \ }\)

Thus, the fraction of the box left after Kim and Courtney have eaten is \(\boxed{\boxed{ \ \frac{3}{8} \ }}.\) \(\boxed{ \ The \ Answer \ }\)

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Quick Steps:

\(\boxed{ \ 1 - \frac{3}{8} - \frac{1}{4} = \ ? \ }\)

\(\boxed{ \ \frac{8}{8} - \frac{3}{8} - \frac{2}{8} = \boxed{ \ \frac{3}{8} \ } \ }\)

The summary scheme is as follows:

Initial conditions

\(\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot} \rightarrow \boxed{ \ one \ part = \frac{8}{8} \ }\)

Kim has eaten ³/₈ of the box: \(\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\) \(\rightarrow \boxed{ \ \frac{3}{8} \ }\)

Courtney has eaten ¹/₄ (or ²/₈) of the box: \(\boxed{\cdot}\boxed{\cdot}\) \(\rightarrow \boxed{ \ \frac{2}{8} \ }\)

Final conditions

\(\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\) is subtracted by \(\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\) and is subtracted by \(\boxed{\cdot}\boxed{\cdot}\) equal \(\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\) as the remaining part \(\rightarrow \boxed{\boxed{ \ \frac{3}{8} \ }}\)

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Keywords: Kim and Courtney, share, a 16-ounce of the box of cereal, ³/₈ of the box, ¹/₄, what fraction of the box is left, ³/₈, subtraction, the denominator, the numerator