Answer:
The base and the height of the parallelogram must be greater than \(8\ meters\)
Step-by-step explanation:
we know that
The area of a parallelogram is equal to
\(A=bh\)
where
b is the base
h is the height
In this problem we have
\(b=h\) -----> given problem
so
\(A=b^{2}\) ----> equation A
\(A> 64\ m^{2}\) ------> inequality B
substitute equation A in the inequality B
\(b^{2}> 64\ m^{2}\)
\(b> 8\ m\)
The base and the height of the parallelogram must be greater than \(8\ meters\)
