alberto rode 5/8 of the water rides at a water park.his sister,reina,rode half of the rides that albeto rode. what fraction of the water rides did reinanot ride? support your answer with a model.
Albert rode 5/8 of the rides which can be simplified to 10/16.
His sister Reina rode half which was 5/16.
Its asking how much did she not ride
So 16/16 - 5/16
Reina did not ride 11/16 of the ride
Answer:
\(\frac{11x}{16}\) rides
Step-by-step explanation:
Let the number of rides at a water part = x
Alberto rode the water rides = \((\frac{5x}{8} )\)
Reina rode half of the rides that Alberto rode = \(\frac{1}{2}\) \((\frac{5x}{8} )\)
= \((\frac{5x}{16} )\)
the water rides did Reina not ride = \(x-\frac{5x}{16}\)
= \(\frac{16x-5x}{16}\)
= \(\frac{11x}{16}\)
\(\frac{11x}{16}\) rides Reina did not ride.