the bleachers at the football game are 7/8 full, and 1/2 of the fans in the bleachers are rooting for the home team. what fraction of the bleachers are filled with home-team fans? justify your procedure.

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Mario299 Mario299 · Answer 1 · 2015-03-24T00:17:40-04:00

First, multiply how much bleachers are filled and how much fans are at the bleachers.

7/8 * 1/2

=

In conclusion, there are fans in the bleachers at the football game that are 7/8 full

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windyyork windyyork · Answer 2 · 2019-08-24T05:49:10-04:00

Answer: Our required fraction would be \(\dfrac{7}{16}\)

Step-by-step explanation:

Since we have given that

Part of the bleachers at the football game = \(\dfrac{7}{8}\)

Part of the fans in the bleachers are rooting for the home team = \(\dfrac{1}{2}\)

So, fraction of the bleachers are filled with home team fans is given by

\(\dfrac{7}{8}\times \dfrac{1}{2}\\\\=\dfrac{7}{8\times 2}\\\\=\dfrac{7}{16}\)

Hence, Our required fraction would be \(\dfrac{7}{16}\)