sabiaonly sabiaonly

21-03-2015
Mathematics

Answered

what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6

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apsweetangel9 apsweetangel9

21-03-2015

d: 1/3x-y+6, A(-9, 12)
md=-b/a=1/1/3=3, md=slope d

d: y-yA=md(x-xA) y-12=3(x+9) y-12=3x+27 => d: 3x-y+15=0

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belcatya belcatya

21-03-2015

y=kx+b
line is perpendicular y=1/3x+6⇒ k=-\(\frac{1}{ \frac{1}{3} }\)=-3

so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture to test solutions in the application

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