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Joseph is building a clone using modeling clay. The cone has a radius of 6 cm and a height of 12 cm Joseph adds additional clay keeping the radius the same until the cone reaches a height of 18 cm how much clay did Joseph add

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W0lf93

So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)pir^2h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)pi(r1^2)h1 - (1/3)+pi(r2^2)h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.

ambitiona

V2: Vd=V2-V1=(1/3)pi(r1^2)h1 - (1/3)+pi(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.

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