if you make a solution by dissolving 1.0 mol of Fecl3 into 1 kg of water how would the osmotic pressure of this solution compare with the osmotic pressure of a solution that is made from 1.0 mol of glucose in 1 kg of water
The osmotic pressure is greaterĀ in the FeCl3 solution. The FeCl3 is an ionic compound, so it dissociates into Fe3+ and 3Cl-, creating 4 overall particles, while the glucose remains as 1 particle. The water increases in the FeCl3 to compensate for that added particle concentration.
Explanation:
Osmotic pressure is defined as the minimum pressure which has to applied on the solution to prevent the entry of the solvent in the solution through a semi-permeable membrane.
It is a type of colligative property which means it depends on the amount of the solution. More the amount, more will be the osmotic pressure.
Mathematically,
\(\pi =icRT\)
\(\pi\) = Osmotic pressure
i = Vant's Hoff factor which is 1 for non-electrolyte solutions
c = Concentration of solution
R = Solution constant
T = temperature
As Ferric chloride is an electrolyte, so it will completely dissociate into its ions.
1 mole of ferric chloride will dissociate into 1 \(Fe^{3+}\) ion and 3 \(Cl^-\) ions.
\(FeCl_3\rightarrow Fe^{3+}+3Cl^-\)
Here, value of i = 4
Glucose is a non-electrolyte and hence will not dissociate into the respective ions. So, value of i = 1
Osmotic pressure will be high for high value of 'i'. Therefore, osmotic pressure of \(FeCl_3\) will be high as compared to the glucose in same amount of water.