Verified Answer :

Hippalectryon

We can first factor all the terms by 2:
6x^2 - 10x - 4=2(3x^2-5x-2)

Then we solve 3x^2-5x-2=0.

Discriminant : 25+432=49=7^2 hence the roots are (5-7)/6 and (5+7)/6 which are -1/3 and 2

Hence 3x^2-5x-2=(x-2)(3x+1)

Thus 6x^2-10x-4=2(x-2)(3x+1)

mariangel

\(6 x^{2} -10x-4\) =

= \(6 x^{2} -12x+2x-4\) =

= 6x(x-2)+2(x-2) =

= (x-2)(6x+2) =

= 2(x-2)(3x+1)


or

Let's solve the equation:

\(6 x^{2} -10x-4\) = 0

Discriminant:

Δ = \(10^{2} -4*6*(-4)\) = 196 = \(14^{2}\)

The roots are:

x1 = \(\frac{10+14}{2*6}\) = \(\frac{24}{12}\) = 2

x2 = \(\frac{10-14}{2*6}\) = \(\frac{-4}{12}\) = \(\frac{-1}{3}\)

so:

\(6 x^{2} -10x-4\) = 6(x-2)(x+\(\frac{1}{3}\)) = (x-2)(6x+2) = 2(x-2)(3x+1)

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