Jujubeezer78 Jujubeezer78

19-03-2015
Mathematics

Answered

Trying to get the solution set of w= square root 8w-12?

Verified Answer :

Hippalectryon Hippalectryon

19-03-2015

Square both sides :

w^2=8w-12 hence w^2-8w+12=0

Discriminant : 64-4*12=16=4^2 hence the solutions could be (8-4)/2, (8+4)/2 which are w=2 and w=6

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konrad509 konrad509

19-03-2015

\(D:8w-12\geq0\\ D:8w\geq12\\ D:w\geq\dfrac{12}{8}\\ D:w\geq\dfrac{3}{2}\\\\ w=\sqrt{8w-12}\\ w^2=8w-12\\ w^2-8w+12=0\\ w^2-2w-6w+12=0\\ w(w-2)-6(w-2)=0\\ (w-6)(w-2)=0\\ w=6 \vee w=2\)

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