Help please!!!!!!! I need help!!!!
The diagonal of a square is \(\sqrt{2}\) times its side, hence its perimeter is \(4*24/\sqrt{2}\approx68\) feet
\(24=a\sqrt2\\ a=\dfrac{24}{\sqrt 2}\\ a=\dfrac{24\sqrt2}{ 2}\\ a=12\sqrt2\\\\ p=4a\\ p=4\cdot12\sqrt2\\ p=48\sqrt2\approx68\)68 ft
