How many kilojoules of heat are required to heat 1.37kg of water from 21.3 to 89.5
q= ? kJ
m= 1.37 kg × \(\frac{1000 g}{1kg}\) =1370 g
c=4.18 J/g° C
ΔΤ= 89.5-21.3=
68.2˚C
?
J = (1370
g) (4.18
J/g˚C) (68.2˚C)
q
= 390,554 J× \(\frac{1kJ}{1000J}\)
q
= 391 kJ
The quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is 390.55 kJ.
The quantity of Heat is the amount of heat energy added or removed from a substance.
The quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is calculated as follows:
mass of water = 1.37 kg = 1370 g
specific heat capacity of water = 4.18 J/g° C
Temperature difference, ΔΤ= 89.5-21.3= 68.2˚C
Q = 1370 g × 4.18 J/g˚C × 68.2˚C
Q = 390,554.12
Q = 390.55 kJ
Therefore, the quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is 390.55 kJ.
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