Answer: The smallest button is first button of size \(\frac{1}{4}\ inch\)
and the greatest button is the second button of size \(\frac{3}{8}\ inch\)
Step-by-step explanation:
Since we have given that
Length of first button is given by
\(\frac{1}{8}\ inch\)
Length of second button is given by
\(\frac{3}{8}\ inch\)
Length of third button is given by
\(\frac{1}{4}\ inch\)
Now, make the denominator :
L.C.M. of 8,8, and 4 is 8
So, Length of third button is given by
\(\frac{1}{4}\times \frac{2}{2}=\frac{2}{8}\ inch\)
So, arrangement will be
\(\frac{1}{8},\frac{2}{8},\frac{3}{8}\)
Hence, The smallest button is first button of size \(\frac{1}{4}\ inch\)
and the greatest button is the second button of size \(\frac{3}{8}\ inch\)
