f(1)=16 f(n)=(n-1)+2n what is f(4)
f(4)=(4-1)+24=11...This seems a bit too easy though, did you mean f(n)=f(n-1)+2n ? In this case :f(1)=16f(2)=16+22=20f(3)=20+23=26f(4)=26+24=34
f(1) = 16f(n) = (n - 1) + 2nf(4) = 64f(4) = (4 - 1) + 2(4)f(4) = 3 + 8f(4) = 11