If the standard kilogram bar kept in Paris were subjected to a net force of 1 newton, what acceleration would it have as a result?
Answer:
It would have an acceleration of \(1\frac{m}{s^{2}}\)
Explanation:
Let's start defining the newton unit (Newton : N)
The N definition is
\(N=Kg.(\frac{m}{s^{2}})\)
Where Kg is kilogram and \(\frac{m}{s^{2}}\) is an acceleration unit.
We can think the definition of newton as :
Given an object with a mass of 1 Kg subjected to a force of 1 N the acceleration that it experiments is \(1\frac{m}{s^{2}}\)
As a result, the standard kilogram bar kept in Paris will experiment an acceleration of \(1\frac{m}{s^{2}}\) If we subject it to a net force of 1 N.