Answered

Simplify. (Polynomials)

  1. (2cd^3)(-2c)(3c^d) =

  2. (2x^2)(3x^6) - (4x^4)(2x^4) =

  3. (6x^2)(3x^6) + (4x^4)(2x^4) =

  4. (2ab^2)^2(-3a^2b^2) =

  5. -6a^3(a^2-2a+1) =

  6. -2xy(x^2-3xy+y^2) =

  7. (a+b) (2a^2-ab+3b^2) =

(Please help asap!)

Verified Answer :

  1. \((2cd^{3})(-2c)(3c^{d})=\\-12c^{d+2}d^{3}\)

    2. \((2x^{2})(3x^{6})-(4x^{4})(2x^{4})=\\6x^{8}-8x^{8}=\\-2x^{8}\)

    3. \((6x^{2})(3x^{6})+(4x^{4})(2x^{4})=\\18^{8}+8x^{8}=\\26x^{8}\)

    4. \((2ab^{2})^{2}(-3a^{2b^{2}})=\\4a^{2}b^{4}(-3a^{2b^{2}})=\\-12a^{2b^{2}+2}b^{4}\)

    5. \(-6a^{3}(a^{2}-2a+1)=\\-6a^{5}+12a^{4}-6a^{3}\)

    6. \(-2xy(x^{2}-3xy+y^{2})=\\-2x^{3}y+6x^{2}y^{2}-2xy^{3}\)

    7. \((a+b)(2a^{2}-ab+3b^{2})=\\2a^{3}-a^{2}b+3ab^{2}+2a^{2}b-ab^{2}+3b^{3}=\\2a^{3}+3b^{3}+a^{2}b+2ab^{2}\)

1.\((2cd^{3})(-2c)(3cd)\)
   \(-12c^{3}d^{4}\)

2.\((2x^{2})(3x^{6}) - (4x^{4})(2x^{4})\)
   \(6x^{8} - 8x^{8}\)
   \(-2x^{8}\)

3.\((6x^{2})(3x^{6}) + (4x^{4})(2x^{4})\)
   \(18x^{8} + 8x^{8}\)
   \(26x^{8}\)

4.\((2ab^{2})^{2}(-3a^{2}b^{2})\)
   \(((2ab^{2})(2ab^{2}))(-3a^{2}b^{2})\)
   \((4a^{2}b^{4})(-3a^{2}b^{2})\)
   \(-12a^{4}b^{6}\)

5.\(-6a^{3}(a^{2} - 2a + 1)\)
   \(-6a^{3}(a^{2}) + 6a^{3}(2a) - 6a^{3}(1)\)
   \(-6a^{5} + 12a^{4} - 6a^{3}\)

6.\(-2xy(x^{2} - 3xy + y^{2})\)
   \(-2xy(x^{2}) + 2xy(3xy) - 2xy(y^{2})\)
   \(-2x^{3}y + 6x^{2}y^{2} - 2xy^{3}\)

7.\((a + b)(2a^{2} - ab + 3b^{2})\)
   \((2a^{3} - a^{2}b + 3ab^{2} + 2a^{2}b - ab^{2} + 3b^{3})\)
   \((2a^{3} - a^{2}b + 2a^{2}b + 3ab^{2} - ab^{2} + 3b^{3})\)
   \(2a^{3} + a^{2}b + 2ab^{2} + 3b^{3}\)