Find the center and radius of x^2+y^2=9
\(x^2+y^2=9\Leftrightarrow (x-0)^2+(y-0)^2=3^2\) hence the center is (0,0) and the radius is 3
\((x-x_1)^2+(y-y_1)^2=r^2\\ \text{center}=(x_1,y_1)\\\\ x^2+y^2=9\\ (x-0)^2+(y-0)^2=9\\ \text{center}=(0,0)\\ r=\sqrt9=3\)
