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Train is traveling at an initial velocity of 68.325m/s. After 23.75 seconds it speeds up to a final velocity of 79.32m/s. What is the train's acceleration during this time

Verified Answer :

SchwarzschildRadius

So,

We know that:
\(acceleration = \frac{ final\ velocity\ -\ initial\ velocity}{time}\)

Plug in the values.
\(acceleration = \frac{79.32 m/s^{2}\ -\ 68.325m/s^{2}}{23.75 secs}\)
\(acceleration = \frac{10.995m/s^{2} }{23.75 secs}\)
\(acceleration = 0.4629 m/s^{2}\)

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