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12 possible outcomes.Sweater ASweater BSweater CSkirt 1Skirt 2Skirt 3Skirt 4Possible ways:A1, A2, A3, A4B1, B2, B3, B4C1, C2, C3, C4
She can choose any one of 3 sweaters. For each choice of sweater . . .She can choose any one of 4 skirts.The total number of different ways to choose an outfit = (3 x 4) = 12 .