find the area of a regular decagon with radius 4 cm
\(A = \frac{5}{2}t^{2} \sqrt{5 + 2 \sqrt{5} }\)
\(A = \frac{5}{2} (4)^{2} \sqrt{5 + 2(2.236067978)} }\)
\(A = \frac{5}{2} (16) \sqrt{5 + 4.472135956}\)
\(A = 40 \sqrt{9.472135956}\)
\(A = 40(3.077683537)\)
\(A = 123.1073415cm^{2}\)