we know that
Eva needs \(\frac{3}{5}\) pound of clay for one piece and \(\frac{7}{10}\) pound of clay for the other piece
Step 1
Find the total pound of clay for the two pieces
\(\frac{3}{5} +\frac{7}{10} =\frac{(2*3+7)}{10} \\ \\ =\frac{13}{10} pounds\)
Eva has \(3\) bags of clay that weigh \(\frac{4}{5}\) pounds each.
Step 2
Find the total weigh of the \(3\) bags of clay
\(3*\frac{4}{5} =\frac{12}{5} pounds\)
Part a ) How many bags of clay will Eva need to make both pieces of pottery?
by using proportion
\(\frac{1}{\frac{4}{5}} =\frac{x}{\frac{13}{10}} \\ \\ \frac{13}{10} =\frac{4}{5} x\\ \\ x=\frac{5*13}{4*10} \\ \\ x=\frac{65}{40} \\ \\ x=1.625bags\)
therefore
the answer Part a)
she needs \(2\) bags
Part b) How many pounds of clay will she have left?
Calculate the total weigh of the \(3\) bags of clay minus the total pound of clay for the two pieces
so
\(\frac{12}{5} -\frac{13}{10} =\frac{(2*12-13)}{10} \\ \\ =\frac{(24-13)}{10} \\ \\ =\frac{11}{10} \\ \\ =1\frac{1}{10} pounds\)
therefore
the answer Part b) is
\(1\frac{1}{10} pounds\)
