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EM09 EM09
  • 14-04-2014
  • Mathematics
Answered

Determine the second derivative of y=cosxtanx.


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Verified Answer :

Anonymous Anonymous
  • 14-04-2014

\(f(x)=cosxtanx\\\\(cosxtanx)'=\left(cosx\cdot\frac{sinx}{cosx}\right)'=(sinx)'=cosx\\\\(cosx)'=-sinx\\\\f''(x)=-sinx\\\\\frac{\delta^2 f}{\delta x^2}=-sinx\)

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