what is the answer to this question
x = 4 y = - 3Substitute x for 4 and y for - 3x² - 4y 24² - 4 *(- 3) 216 - ( - 12 ) 216 + 12 228 = 14 2Solution: 14
\(\frac{x^2-4y}{2} = \frac{4^2-4*(-3)}{2} = \frac{16+12}{2} = \frac{28}{2} =14\)