\(\begin{cases} x+y=92 \\x-y=20 \end{cases}\\+-------\\2x=112\ \ | \ divide \ both \ sides\ by\ 2\\x=56\\\\x+y=92\\56+y=92\\y=92-56\\y= 36\\\\\begin{cases} x=56 \\y=36 \end{cases}\\\\Answer:\ \ Therefore, \ the \ two \ numbers \ are \ 36 \ and \ 56\)
