How do I solve 28=64-9x^2 using square roots?
\(28=64-9{ x }^{ 2 }\\ \\ 9{ x }^{ 2 }=64-28\\ \\ 9{ x }^{ 2 }=36\)
\(\\ \\ \frac { 1 }{ 9 } \cdot 9{ x }^{ 2 }=\frac { 1 }{ 9 } \cdot 36\\ \\ { x }^{ 2 }=4\\ \\ x=\pm \sqrt { 4 }\)
\(\\ \\ \therefore \quad x=\pm 2\)