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You're conducting a physics experiment on another planet. You drop a rock from a height of 2.3 m and it hits the ground 1.1 seconds later. What is the acceleration due to gravity on this planet?

A4.2 m/s2
B3.8 m/s2
C2.4 m/s2
D9.8 m/s2

Verified Answer :

You get \(2.3=1.21*\frac{a}2\) or \(4.6=1.21a\) or \(a=3.802\) (B)

Acceleration due to gravity on this planet will be 3.802 m / s^2

What are equations of motion?

Equation of motion are defined as equations that describe the behavior of a physical system in terms of its motion as a function of time

Using equation of motion

u=0

s= 2.3 m

t = 1.1 sec

to find = g (acceleration due to gravity on this planet)

s = u t + 1/2 (a ) (t ^(2))

s = 1/2 (g) (t^2)

2.3 = 1/2 (g) (1.1^2)

g = 2 * 2.3 /(1.1)^2

g = 4.6 /1.21= 3.802

correct answer is b) g = 3.802 m / s^2

Learn more about equation of motion

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