Using the principle of conservation of mechanical energy, calculate the maximum height achieved by a 7 N ball tossed vertically upward with an initial velocity of 10 m/s.
Because mechanical energy is conserved, potential energy due to gravity will equal the kinetic energy of the used to throw the ball. This is represented by mgh=.5mv^2
1. Divide both sides of the equation by m to ignore mass. The new equation will be gh=.5v^2
2. Substitute values into the equation: 9.8h=(.5)(10^2)--> 9.8h=50
3. Divide 50 by 9.8 to get h=5.102m
Explanation:
Given that
The weight of a ball, \(W=7\ N\)
Initial velocity of the ball, \(v=10\ m/s\)
The principle of conservation of mechanical energy states that, the total energy of a system remains conserved. The mathematical form of the principle of conservation of mechanical energy is :
\(\dfrac{1}{2}mv^2=mgh\)
Where
m is the mass of the object
v is the velocity
h is the height
Using the conservation of energy,
\(\dfrac{1}{2}mv^2=mgh\\\\\dfrac{1}{2}v^2=gh\)
Solving for h,
\(h=\dfrac{v^2}{2g}\)
Put all the values,
\(h=\dfrac{(10)^2}{2\times 9.8}\\\\h=5.10\ m\)
Answer:
The maximum height achieved by the ball is \(5.1\ m\).
Reference:
brainly.com/question/20971995