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A helicopter rose vertically 300m and then flew west 400m. how far was the helicopter from it starting point?

Verified Answer :

Sara63

\(a^{2} + b^{2} = c^{2} 300 ^{2} + 400 ^{2} = c^{2} c^{2} =250,000 \sqrt{250,000} =500m\)




The helicopter rose vertically, and then flew horizontally, so it's final displacement (distance from where it is now to where it started) is in the shape of a triangle.

The displacement is the hypotenuse of this triangle, with sides 300m and 400m.

We can work out this distance using Pythagorus' theorem, because we know that;

\(a^{2} = b^{2} + c^{2}\)

Where \(a\) is the hypotenuse, and \(b\) and \(c\) are the two other sides. So;

\(a^{2} = b^{2} + c^{2} \\ \\ a^{2} = 300^{2} + 400^{2} \\ \\ a^{2} = 90000 + 160000 \\ \\ a = \sqrt{250000} \\ \\ a = \boxed{500m}\)