Simplify please (x^2/9x^2-4y^2)/(x^2/2y-3x)
9x²-4y²=(3x-2y)*(3x+2y)Solution: \(\frac{ x^{2} }{(3x-2y)*(3x+2y)} : \frac{x^2}{2y-3x} = \frac{ x^{2} }{(3x-2y)*(3x+2y)} * \frac{2y-3x}{x^2} \\ \\ =- \frac{1}{3x+2y}\)
x² ÷ x² = x² × 2y - 3x = -x + y9x² - 4y² 2y - 3x 9x² - 4y² x² 2x - 3y