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The prism has a surface area of 202 ft2.




What would the surface area of the prism be if each dimension were tripled?




ft2

Verified Answer :

arnfrs

Let's call the dimensions of the prism (I will assume it is rectangular) a, b, and c.

The surface area is:

\(2ab + 2ac + 2bc = 202\)

The dimensions of the new prism are 3a, 3b, and 3c.

This surface area would be:

\(2(3a)(3b) + 2(3a)(3c) + 2(3b)(3c) =\)

\(2(9ab) + 2(9ac) + 2(9bc) =\)

\(9(2ab + 2ac + 2bc) =\)

\(9(202) = \boxed{1818}\)

Hope this helps :D


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