Given a>0 and b>0, which inequality shows the result of solving -ax/b >/ (c-d) for x?

a)x </ ad-ac/b

b)x </ bd-bc/a

c)x >/ bc-bd/a

d)x >/ bd-bc/a


Verified Answer :

\(-\dfrac{ax}{b}\geq c-d\\ -ax\geq bc-bd\\ x\leq-\dfrac{bc-bd}{a}\\ x\leq\dfrac{bd-bc}{a}\)

We will see that the solution of the given inequality is:

\(\frac{ -(c - d)*b}{a} \ge x\)

How to solve the inequality?

Here we have the inequality:

\(-\frac{ax}{b} \ge c - d\)

To solve it, we need to isolate x on one side of the inequality.

First, we can multiply both sides for b:

\(-ax \ge (c - d)*b\)

Now we divide both sides by -a, because we are operating with a negative number, we need to change the direction of the greater than or equal to sign, so we will get:

\(\frac{ -(c - d)*b}{a} \ge x\)

That is the solution to the given inequality.

If you want to learn more about inequalities:

https://brainly.com/question/18881247

#SPJ2