Given a>0 and b>0, which inequality shows the result of solving -ax/b >/ (c-d) for x?
a)x </ ad-ac/b
b)x </ bd-bc/a
c)x >/ bc-bd/a
d)x >/ bd-bc/a
\(-\dfrac{ax}{b}\geq c-d\\ -ax\geq bc-bd\\ x\leq-\dfrac{bc-bd}{a}\\ x\leq\dfrac{bd-bc}{a}\)
We will see that the solution of the given inequality is:
\(\frac{ -(c - d)*b}{a} \ge x\)
Here we have the inequality:
\(-\frac{ax}{b} \ge c - d\)
To solve it, we need to isolate x on one side of the inequality.
First, we can multiply both sides for b:
\(-ax \ge (c - d)*b\)
Now we divide both sides by -a, because we are operating with a negative number, we need to change the direction of the greater than or equal to sign, so we will get:
\(\frac{ -(c - d)*b}{a} \ge x\)
That is the solution to the given inequality.
If you want to learn more about inequalities:
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