class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an A on the test, and 35% of the class are girls and scored an A on the test. If a student is chosen at random and is found to be a girl, the probability that the student scored an A is
if you add 55% and 45% the total is 100% so 45/100 are girls. 35% of the girls scored and A so 35/45 is the probability that it is a girl chosen or 7/9. the probability is 7 out of 9
The probability that a girl chosen scored A is ⁷/₉
Given;
number of boys in the class, = 55%
number of girls in the class, = 45%
number of the boys who scored A = 25%
number of girls who scored A = 35%
To find:
the probability that a girl chosen scored A
The fraction of the boys who score A:
\(= \frac{25}{55} = \frac{5}{11}\)
The fraction of the girls who scored A:
\(= \frac{35}{45} = \frac{7}{9}\)
Thus, the probability that a girl chosen scored A is ⁷/₉
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