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Consider the Zn(s) + Cu+2(aq) + Zn+2(aq) +Cu(s) system.


Which element was the electron donor?

Verified Answer :

JoshEast

The electron donor in the reaction is the Zn and as a result it is oxidised to Zn²⁺.  A move from an oxidation state of 0 to 2 (Oxidation is the Loss of Electron)

Answer: Zinc element was the electron donor

Explanation:

\(Zn(s)+Cu+2(aq)\rightarrow Zn^{+2}(aq)+Cu(s)\)

In the given reaction, the zinc metal is getting oxidized to zinc ion by loosing 2 electrons and copper ion are getting reduced to copper by gaining 2 electrons.

\(Zn\rightarrow Zn^{2+}+2e^-\)

\(Cu^{2+}+2e^-\rightarrow Cu\)

So, in the given reaction zinc is an element which donates its electrons.Hence, electron donor was the zinc element.

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