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A 2-kg bowling ball rolls at a speed of 10 m/s on the ground.


Circle one: KE / GPE / both


Show your work for finding the values of each type of energy the object has

Verified Answer :

the KE can be solve using the formula:
ke = 0.5 mv^2
where m is the mass of the object
v is the velocity
ke = 0.5 ( 2 kg ) ( 5 m/s)^2
ke = 25 J

the GPE can be solved using the formula:
GPE = mgh
where m is the mass
g is the acceleration due to gravity ( 9.81 m/s^2)
h is the height

GPE = ( 4 kg)(9.81 m/s^2)( 40 m)
GPE = 392.4 J

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