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When 0.1625 g of magnesium is burned in a bomb calorimeter that has a heat capacity of 3.03 kJ/ ∘

C, the temperature increases by 1.252 ∘

CHow much heat (kJ/mol) is liberated during the burning of the magnesium?

Verified Answer :

Heat
lost in a system can be calculated by multiplying the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:


Heat = C(T2-T1)

Heat =  (3.03) (1.252)
Heat = 3.79 kJ /mol of heat is liberated

Answer: Heat released during the burning of 0.1625 g of magnesium is 3.79356 kilo Joules.

Explanation:

Mass of the magnesium : 0.1625 g

Heat capacity of the bomb calorie-meter,C = 3.03 kJ/°C

Change or increase in temperature \(\Delta T\)= 1.252°C

Heat = \(C\times \Delta T=3.03 kJ/^oC\times 1.252^oC=3.79356 kJ\)

Heat released during the burning of 0.1625 g of magnesium is 3.79356 kilo Joules.

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