Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.
The volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm = 7,680cm^3
Answer: \(\text{V}=7,680\ cm^3\)
Step-by-step explanation:
The volume of a pyramid is given by :-
\(\text{Volume}=\dfrac{1}{3}\text{base area *height}\)
Given: Slant height of the pyramid (l)= 26 cm
The base edge of the pyramid (s)=48 cm
Now, the height of the pyramid is given by :
\(h=\sqrt{l^2-(\dfrac{s}{2})^2}\\\\\Rightarrow\ h=\sqrt{26^2-(\dfrac{48}{2})^2}\\\\\Rightarrow\ h=10\ cm\)
Now, the volume of the square pyramid is given by :-
\(\text{V}=\dfrac{1}{3}(48)^2(10)\\\\\Rightarrow\ \text{V}=7680\ cm^3\)