The energy released when a certain amount of a substance condenses to a liquid is given by:
\(Q=m \lambda_v\)
where m is the mass of the substance and \(\lambda_v\) is the latent heat of vaporization.
In this problem, the mass is m=0.06 kg, while the latent heat of vaporization of mercury is \(\lambda_v=296 kJ/ kg\). Therefore, if we apply the formula we get:
\(Q=(0.06 kg)(296 kJ/ kg)=17.76 kJ=17760 J\)
So, the correct answer is
C. 17,705.1 J
