which of the following functions has a rate of change that stays the same?


y=x^2-5x-14

y=19x-10

y=5^x

y=0.03x^2+11x+1

which of the following functions has a rate of change that stays the same? y=x 2-5x-14 y=19x-10 y=5 x y=0.03x 2+11x+1 class=

Verified Answer :

For polynomials, if we say of "rate of change", we are talking about the slope of the tangent line. That is the value of dy/dx or the differential of y in terms of x. From the given choices, the answer would be the second choice, y = 19x - 10. This is because dy/dx in this item is essentially equal to 19 which is a constant.

The rate of change of a function with respect to x is known as the slope. The slope is constant for the function y = 19x - 11.

What is differentiation?

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

The functions are as follows;

\(\rm a. \ \ y=x^2-5x-14\\\\b. \ \ y=19x-10\\\\c. \ \ y=5^x\\\\d. \ \ y=0.03x^2+11x+1\)

The rate of change of the function is called the slope of that function at a point.

a.  \(\rm y=x^2-5x-14\)

Differentiate the function with respect to x, then we have

\(\rm \dfrac{dy}{dx}=2x-5\)

b.  \(\rm y=19x-10\)

Differentiate the function with respect to x, then we have

\(\rm \dfrac{dy}{dx}=19\)

c.  \(\rm y=5^x\)

Differentiate the function with respect to x, then we have

\(\rm \dfrac{dy}{dx}= ln 5 * 5^x\)

d.  \(\rm y=0.03x^2+11x+1\)

Differentiate the function with respect to x, then we have

\(\rm \dfrac{dy}{dx}=0.06x + 11\)

Thus, the slope is constant for the function y = 19x - 11.

More about the differentiation link is given below.

https://brainly.com/question/24062595