Answer:
The perimeter of the square is \(31.96\ m\)
Step-by-step explanation:
we know that
The perimeter of a square is equal to
\(P=4b\)
where
b is the length side of the square
Step 1
Find the length side of the square
The diagonal of the square is equal to
Applying the Pythagoras Theorem
\(d^{2} =b^{2}+b^{2}\\d^{2}=2b^{2}\\d=b \sqrt{2}\)
In this problem we have
\(d=11.3\ m\)
\(d=b\sqrt{2}\) ------> solve for b
\(b=d/\sqrt{2}\)
substitute the value of d
\(b=11.3/\sqrt{2}\ m\)
Step 2
Find the perimeter of the square
\(P=4b\)
Substitute the value of b
\(P=4(11.3/\sqrt{2})=31.96\ m\)
