A rectangle's length is 6 units greater than its width. Write an equation expressing the rectangle's area, A, as a function of w. A) A = 2w + 6 B) A = 4w + 12 C) A = w2 + 6w D) A = w2 + 12w
I hope this helps you
length =width +6
Area=width × length
Area=w. (w+6)
Answer:
Option C is correct.
an equation expressing the rectangle's area , \(A = w^2+6w\)
Step-by-step explanation
Area of rectangle(A) is given by:
\(A = lw\)
where,
l is the length of the rectangle and w is the width of the rectangle.
As per the statement:.
A rectangle's length is 6 units greater than its width
⇒\(l = 6+w\)
Substitute in the above formula;a we have;
\(A = (6+w) \cdot w\)
Using distributive property we have;
\(A = 6w+ w^2\)
or
\(A = w^2+6w\)
Therefore, an equation expressing the rectangle's area is, \(A = w^2+6w\)