Answer:
The function f(x)= \(x^2-12x+20\) has zeroes at x=10 and x=2.
Step-by-step explanation:
Given the zeroes of the function at x=10 and x=2
x=10
x-10=0
x=2
x-2=0
Now , the factors of the function are (x-10) and (x-2)
The function can be obtain by multiplying these factors then we can write
f(x)=\((x-10)(x-2)\)
f(x)=\(x(x-2)-10(x-2)\)
f(x)=\(x^2-2x-10x+20\)
f(x)=\(x^2-12x+20\)
Hence, the function is f(x)=\(x^2-12x+20\) and the zeroes of function at x=10 and x=2.
