Which linear inequality is represented by the graph?

y < 3x + 2

y > 3x + 2

y < x + 2

y > x + 2

Which linear inequality is represented by the graph? y lt; 3x + 2 y gt; 3x + 2 y lt; x + 2 y gt; x + 2 class=

Verified Answer :

Answer-

\(\boxed{\boxed{y > 3x + 2}}\)

Solution-

From the graph, the coordinates of two present on the line are, (0, 2), (-3, -7)

Applying two point formula for straight line,

\(\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}\)

Here,

x₁ = 0

y₁ = 2

x₂ = -3

y₂ = -7

Putting in the formula,

\(\Rightarrow \dfrac{y-2}{-7-2}=\dfrac{x-0}{-3-0}\)

\(\Rightarrow \dfrac{y-2}{-9}=\dfrac{x}{-3}\)

\(\Rightarrow \dfrac{y-2}{3}=\dfrac{x}{1}\)

\(\Rightarrow \dfrac{y-2}{3}=x\)

\(\Rightarrow {y-2}=3x\)

\(\Rightarrow y=3x+2\)

As we have got the equality equation, now we have to care about the sign.

So option 3 and 4 are not the correct options.

Putting origin (0, 0) in the first equation i.e \(y < 3x + 2\),

\(\Rightarrow 0<3(0)+2\\\\\Rightarrow 0<2\)

As this satisfies the equation the shaded region will be towards origin or right side of the line \(y=3x+2\). This area is the opposite to the desired area, so this is not the right answer.

Putting origin (0, 0) in the second equation i.e \(y > 3x + 2\),

\(\Rightarrow 0>3(0)+2\\\\\Rightarrow 0 gtr 2\)

As this does not satisfy the equation the shaded region will be opposite to origin or left side of the line \(y=3x+2\), so this is the right answer.

The linear equality represented by the graphis \(\boxed{{\mathbf{y > 3x + 2}}}\) and it matches with \(\boxed{{\mathbf{OPTION B}}}\).

Further explanation:

It is given that a line passes through points \(\left( {0,2} \right)\) and \(\left({ - 3, - 7}\right)\) as shown below in Figure 1

The slope of a line passes through points \(\left({{x_1},{y_1}}\right)\) and \(\left({{x_2},{y_2}}\right)\) is calculated as follows:

\(m=\dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}\)       ......(1)

Here, the slope of a line is denoted as \(m\) and points are  \(\left({{x_1},{y_1}}\right)\) and \(\left({{x_2},{y_2}}\right)\).

Substitute \(0\) for \({x_1}\) , \(2\) for \({y_1}\) , \(-3\) for \({x_2}\) and \(-7\) for \({y_2}\) in equation (1) to obtain the slope of a line that passes through points \(\left({0,2}\right)\) and \(\left({ - 3, - 7}\right)\).

\(\begin{aligned}m&=\frac{{ - 7 - 2}}{{ - 3 - 0}}\\&=\frac{{ - 9}}{{ - 3}}\\&=3\\\end{aligned}\)

Therefore, the slope is \(3\).


The point-slope form of the equation of a line with slope \(m\) passes through point \(\left({{x_1},{y_1}}\right)\) is represented as follows:

\(y - {y_1}= m\left({x - {x_1}}\right)\)         ......(2)

Substitute \(0\) for \({x_1}\) , \(2\) for \({y_1}\) and   \(3\) for \(m\) in equation (2) to obtain the equation of line.


\(\begin{aligned}y - 2&=3\left({x - 0}\right)\\y - 2&=3x\\y&=3x + 2\\\end{aligned}\)

Therefore, the value of \(y\) is \(3x + 2\).

Since the shaded part in Figure 1 is above the equation of line \(y = 3x + 2\), therefore, greater than sign is used instead of is equal to.


Thus, the linear inequality is \(y > 3x + 2\) as shown below in Figure 2.


Now, the four options are given below.

\(\begin{aligned}{\text{OPTION A}} \to y < 3x + 2 \hfill\\{\text{OPTION B}} \to y > 3x + 2 \hfill\\{\text{OPTION C}} \to y < x + 2 \hfill\\{\text{OPTION D}} \to y > x + 2 \hfill\\\end{aligned}\)

Since OPTION B matches the obtained equation that is \(y > 3x + 2\).


Thus, the linear equality represented by the graph is \(\boxed{{\mathbf{y > 3x + 2}}}\) and it matches with \(\boxed{{\mathbf{OPTION B}}}\).

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Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords:Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics,equation of line, line, passes through point, inequality

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