Answered

Ten grams of a gas occupies 12.5 liters at a pressure of 42.0 cm Hg. What is the volume when the pressure has increased to 75.0 cm Hg? 6.00 L 7.00 L 8.00 L none of the above

Verified Answer :

rahmasaleh00

Using boyles law
12.5×42=75×v
So.v=7l

transitionstate

Answer:

             7.0 L

Solution:

              According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportinal to the applied Pressure". Mathematically, the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂    ----------- (1)

Data Given;

                  P₁  =  42.0 cm Hg

                  V₁  =  12.5 L

                  P₂  =  75.0 cm Hg

                  V₂  =  ??

Solving equation 1 for V₂,

                   V₂  =  P₁ V₁ / P₂

Putting values,

                   V₂  =  (42.0 cm Hg × 12.5 L) ÷ 75.0 cm Hg

                   V₂  =  7.0 L

Result:

          As the Pressure has increased from 42.0 cm Hg to 75.0 cm Hg, therefore, Volume got decreased from 12.5 L to 7.0 L.

Related Questions